How can I find the peak result of a combination of two harmonic analyses?
|
The most rigorous way to obtain the peak value of the combined result is to check every possible phase angle combination between the two excitations. That would require a lot of expansion passes, but they tend to run quickly. The input below shows how you could do this. To be accurate you would need to check at closer intervals than the 30 degrees used in this input file. The number of solutions is (360/interval)^2, which could be prohibitive. You could assume that the maximum combined result is the sum of the maximums in which case you only need to solve 2*(360/interval) times. /prep7 et,1,42 mp,ex,1,1e7 mp,nuxy,1,.3 mp,dens,1,.00025 rect,,20,,1 esize,.5 amesh,1 nsel,s,loc,x,0 d,all,all nsel,all fini /solu antype,modal modop,lanb,10 mxpand,10 solve fini /solu antyp,harm hropt,msup dmprat,.02 harf,,90 nsub,1 nsel,s,loc,x,20 f,all,fx,100 nsel,all solve harf,,100 fdele,all,all nsel,s,loc,x,20 f,all,fy,20 nsel,all solve fini /solu expass,on numexp,all solve fini /post1 set,list *do,iii,30,360,30 *do,jjj,30,360,30 /gopr hrcplx,1,1,iii lcwrite,99,ls1,lc99 hrcplx,1,2,jjj lcfile,99,ls1,lc99 lcoper,add,99 ! Retrieve max displacement nsort,u,sum *get,U_max,sort,,max *get,Node_max,sort,,imax *enddo *enddo |
||
|