# Do you have an example that shows exactly how NFORCE calculates its values in a full harmonic response analysis?

 Yes, please see the ANSYS 9.0 input below (which is also attached to this solution record as "nforce.inp"). This input consists of two blocks that are connected together by CP (coupled DOF) commands. One end is fixed and the other end of the cantilever has a tip load applied to it with both real and imaginary components. The element data is squared, then summed, then the square root is taken, and then the data from each each element is summed at a given node. The details are highlighted in the output results ...fini/clear/title, SRSS Test in Full Harmonic Response Analysis/plopts,info,1/view,,1,2,3/pnum,type,1/num,1/prep7et,1,SOLID45et,2,SOLID45r,1mp,ex,1,30.0e6mp,nuxy,1,0.30mp,dens,1,0.0007block,0,5,0,1,0,1block,5,10,0,1,0,1esize,0.50type,1vmesh,1n11=node(5.0,0.0,0.0)n12=node(5.0,0.0,0.5)n13=node(5.0,0.0,1.0)n14=node(5.0,0.5,0.0)n15=node(5.0,0.5,0.5)n16=node(5.0,0.5,1.0)n17=node(5.0,1.0,0.0)n18=node(5.0,1.0,0.5)n19=node(5.0,1.0,1.0)nsel,nonetype,2vmesh,2n21=node(5.0,0.0,0.0)n22=node(5.0,0.0,0.5)n23=node(5.0,0.0,1.0)n24=node(5.0,0.5,0.0)n25=node(5.0,0.5,0.5)n26=node(5.0,0.5,1.0)n27=node(5.0,1.0,0.0)n28=node(5.0,1.0,0.5)n29=node(5.0,1.0,1.0)nsel,allcp,,all,n11,n21cp,,all,n12,n22cp,,all,n13,n23cp,,all,n14,n24cp,,all,n15,n25cp,,all,n16,n26cp,,all,n17,n27cp,,all,n18,n28cp,,all,n19,n29eplotfini/soluantype,modalmodopt,lanb,10 ! block Lanczos modal analysismxpand,10,,,yesnsel,s,loc,x,0.0d,all,all,0.0nsel,allsolvesave*get,freq1,mode,1,freq ! 1st frequency*get,freq2,mode,2,freq ! 2nd frequency*get,freq3,mode,3,freq ! 3rd frequency*get,freq4,mode,4,freq ! 4th frequency*get,freq5,mode,5,freq ! 5th frequency*get,freq6,mode,6,freq ! 6th frequencyfini! MODE FREQUENCY(HERTZ)!! 1 334.7519161629! 2 334.7519161638! 3 2027.060147620! 4 2027.060147620! 5 3210.528718405! 6 5201.027253448! 7 5417.594104150! 8 5417.594104150! 9 9651.400218760! 10 10029.39527864/prep7mp,dmpr,1,0.10 ! constant material damping coefficientfini/soluantype,harmic ! harmonic response analysishropt,full ! full harmonic responsehrout,off ! print results asamplitudes and phase anglesoutpr,basic,1harfrq,0.99*freq4 ! close to 4th natural frequencykbc,1 ! step applied boundary conditionsnsel,s,loc,x,10.0nsel,r,loc,y,1.0f,all,fy,1.0,0.5 ! real and imaginary tip load ...nsel,allsolvesavefini/post1/graph,fullforce,total ! NFORC uses FORCE,TOTAL by default*status,n16*status,n26nsel,s,node,,n16 ! block 1 node with two elements summednsel,a,node,,n26 ! corresponding block 2 node ...eslnset,,, ,,, ,1 ! real datapresol,fset,,, ,,, ,2 ! imaginary datapresol,fhrcplx,,,360 ! amplitude values for omegat=360presol,fnforce/eof= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = ***** ANSYS RESULTS INTERPRETATION (POST1) ***** Use Full element graphics for all elements USE TOTAL FORCES FOR SOLUTION RESULTS NAME VALUE TYPE DIMENSIONS N16 46.0000000 SCALAR. NAME VALUE TYPE DIMENSIONS N26 156.000000 SCALAR= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = == == = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = USE DATA SET 1 ON RESULT FILE FOR LOAD CASE 0 TIME/FREQUENCY= 2006.8 PRINT F ELEMENT SOLUTION PER ELEMENT ***** POST1 ELEMENT NODE TOTAL FORCE LISTING ***** LOAD STEP= 1 SUBSTEP= 1 FREQ= 2006.8 LOAD CASE= 0 THE FOLLOWING X,Y,Z FORCES ARE IN GLOBAL COORDINATES ELEM= 30 FX FY FZ 77 2.3575 -0.15698 0.24832E-01 68 -2.6409 0.80705E-01-0.72433E-02 90 -1.1190 0.10444 -0.13653E-02 99 1.3801 -0.19393 0.74470E-02 44 2.3530 -0.17279 -0.35565E-01 35 -2.6361 0.90853E-01 0.22767E-01 46-1.0987 0.11456 0.49823E-02 => (FX_R1)**2= 1.2071417 66 1.3988 -0.20969 -0.16887E-01 ELEM= 40 FX FY FZ 99 -1.3801 -0.19393 -0.74470E-02 90 1.1190 0.10444 0.13653E-02 78 2.6409 0.80705E-01 0.72433E-02 88 -2.3576 -0.15698 -0.24832E-01 66 -1.3988 -0.20969 0.16887E-01 46 1.0987 0.11456 -0.49822E-02 => (FX_R2)**2 = 1.2071417 45 2.6361 0.90853E-01-0.22767E-01 48 -2.3530 -0.17279 0.35565E-01 ELEM= 61 FX FY FZ 166 2.6416 -0.10545 0.18075E-01 168 -2.7989 0.28410E-01 0.85658E-04 190 -1.2864 0.38538E-01 0.67368E-03 188 1.4337 -0.12925 0.56061E-02 133 2.6368 -0.11566 -0.22945E-01 135 -2.7941 0.32767E-01 0179 -4.5650 0.47156E-01 0.17930E-01 178 4.5789 0.42510E-01 0.16974E-01 156 2.2815 0.59681E-01-0.11343E-01 => (FX_I4)**2 = 5.2052423 157 -2.2870 0.67503E-01-0.12237E-01 155 -4.5561 0.53074E-01-0.13897E-01 146 4.5693 0.47764E-01-0.11440E-01= = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = HRCPLX MACRO FREQUENCY= NEAR 0.00 ANGLE= 360.000 PRINT F ELEMENT SOLUTION PER ELEMENT SRSS Test in Full Harmonic Response Ana FREQ=2006.789 AMPLITUDE ***** POST1 ELEMENT NODE TOTAL FORCE LISTING ***** CALCULATED LOAD CASE= 0 THE FOLLOWING X,Y,Z FORCES ARE IN GLOBAL COORDINATES ELEM= 30 FX FY FZ 77 4.9402 0.21806 0.40886E-01 68 5.2877 0.23761 0.88031E-02 90 2.3958 0.26368 0.31141E-02..99 2.7189 0.271710.12753E-01 44 4.9295 0.24102 0.51969E-01 35 5.2770 0.24905 0.26377E-01 46 2.3701 0.27521 0.60630E-02 => FX_A1 = (1.2071417 + 4.4053812)**0.5 66 2.7413 0.29471 0.27381E-01 = (5.6125229)**0.5 = 2.3690764 ELEM= 40 FX FY FZ 99 2.7189 0.27171 0.12753E-01 90 2.3958 0.26368 0.31141E-02 78 5.2877 0.23761 0.88032E-02 88 4.9402 0.21806 0.40886E-01 66 2.7413 0.29471 0.27381E-01 46 2.3701 0.27521 0.60629E-02 => FX_A2 = (1.2071417 + 4.4053812)**0.5 45 5.2770 0.24905 0.26377E-01 = (5.6125229)**0.5 = 2.3690764 48 4.9295 0.24102 0.51969E-01 ELEM= 61 FX FY FZ 166 5.2865 0.13316 0.25274E-01 168 5.3611 0.14057 0.18385E-01 190 2.6280 0.15113 0.65027E-02 188 2.6967 0.15585 0.83738E-02 133 5.2758 0.14262 0.25719E-01 135 5.3509 0.14494 0.17240E-01 157 2.6214 0.15646 0.12272E-01 156 2.7001 0.16624 0.16725E-01=> FX_A3 = (2.0845584 + 5.2052423)**0.5.= (7.2898007)**0.5 = 2.6999631 ELEM= 71 FXFYFZ 188 2.6967 0.15585 0.83737E-02 190 2.6280 0.15113 0.65028E-02 179 5.3612 0.14058 0.18386E-01 178 5.2865 0.13316 0.25273E-01 156 2.7002 0.16624 0.16725E-01 => FX_A3 = (2.0848472 + 5.2052423)**0.5 157 2.6214 0.15645 0.12272E-01 = (7.2900895)**0.5 = 2.7000166 155 5.3510 0.14494 0.17240E-01 146 5.2758 0.14262 0.25719E-01= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = ***** POST1 NODAL TOTAL FORCE SUMMATION ***** LOAD STEP= 9999 SUBSTEP= 0 THE FOLLOWING X,Y,Z FORCES ARE IN GLOBAL COORDINATES NODE FX FY FZ 46 4.740 0.5504 0.1213E-01 => FX_ASUM = 2.3690764 + 2.3690764 = 4.7381528 156 5.400 0.3325 0.3345E-01 => FX_ASUM = 2.6999631 + 2.7000166 = 5.3999797 ***** SUMMATION OF TOTALFORCES AND MOMENTS IN GLOBAL COORDINATES ***** FX = 10.14055 FY = 0.8828991 FZ = 0.4557521E-01MX = -0.8601115 MY = 9.912676 MZ = -0.6557808 SUMMATION POINT= 0.0000 0.0000 0.0000= = = = = = = = = = = = = = = = = = = = = = = = = = = =