Q. Why do I get surface temperatures HOTTER than my radiation source when using radiation in CFX? This seems to happen at the boundary b/w a symmetry plane and an adiabatic boundary.
A. In all likelihood, CFX has simply not converged yet. Radiation is of course highly non-linear. It is best to use as large a physical time step as possible (1.E+5 seconds as opposed to, say, 50 seconds) when solving Conjugate Heat Transfer problems in CFX.
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Q. Why do I get surface temperatures HOTTER than my radiation source when using radiation in CFX? This seems to happen at the boundary b/w a symmetry plane and an adiabatic boundary. A. In all likelihood, CFX has simply not converged yet. Radiation is of course highly non-linear. It is best to use as large a physical time step as possible (1.E+5 seconds as opposed to, say, 50 seconds) when solving Conjugate Heat Transfer problems in CFX. |
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